SAT MATH question !!!

<ol>
<li><p>Of the 60 people in a room, 2/3 are women and 2/5 are married. What 's the max # of women in the room who can be unmarried ?
a. 16 b. 24 c.34 d.36 e. 40</p></li>
<li><p>If 27√27=a√b, a&b are both positive integers and a<b, which of the following could be the value of ab?
a. 6561 b. 729 c. 243 d. 81 e.27 </p></li>
</ol>

<p>correct answer to 1. d 2. c</p>

<p>
[quote]
To find the maximum number of women in the room who can be unmarried, you must minimize the number of women in the room who are married.

[/quote]
</p>

<p>There are 60 people in the room;
40 people are women; 20 people are men.
24 people are married.</p>

<p>Let's make all the men and 4 women married;
40 - 4 = 36 women who can be unmarried.</p>

<p>For the first question
2/3 of 60 = # of women = 40
3/5 of 60 = # of unmarried ppl = 36
max possible # of unmarried women = 36</p>

<p>I'm not sure about the second one... I hope that makes sense!</p>

<p>
[quote]
2. If 27√27=a√b, a&b are both positive integers and a<b, which of the following could be the value of ab?
a. 6561 b. 729 c. 243 d. 81 e.27

[/quote]
</p>

<p>Did you mean a>b?</p>

<p>27√27 = a√b;
27√(9<em>3) = a√b;
(27</em>3)√3 = a√b;
81√3 = a√b;</p>

<p>81 * 3 = 243</p>

<p>JefferyJung
I mean a<b, and that is why I chose A.</p>

<p>27√27= (9<em>3)√27 -> 9=√81 so (9</em>3)√27= 3√(27*81)= 3√2187=a√b and if a<b, then="" the="" answer="" is="" 3(2187)="6561." if="" correct="" c,="" you="" must="" mean="" a="">b, that's the only condition that will result in 243.</b,></p>