<p>Wow I got that right, any other hard ones to discuss</p>
<p>@TheCudLife
I’m pretty sure the answer is 1.2. I used 100 for teachers and 200 for students.
100 x 1.08 = 108
200 x .9 = 180
(108/180)/(100/200) = 1.2</p>
<p>Yeah, 16 (pi-1) and 34 perimeter. </p>
<p>You just made the marble one seem so much easier, lol.</p>
<p>How about the one that said something like “P is represented by x on a line segment. If P is twice as far from 3 as from another point…” I can barely remember it but I know I was torn between A and C and picked C.</p>
<p>I’m pretty sure t was the smallest. It said t is 15 percent of p, and t is r percent of 20. Plug in p = 100, then t = 15. Which means r = 75. So t < r < p.</p>
<p>The “P on the number line” question was A. Substitute -3 for P (because its distance from the number 3, which is 6, is twice its distance from 0) and plug it in to A, which is the only one that works.</p>
<p>@Nihility
It was C cause if you picked 1 for P, both A and C worked. But P could also be -3, and that didn’t work for A.</p>
<p>@Nihility </p>
<p>t<r<p</p>
<p>@Xerdge yea that one is definitely 1.2, I used lots of different numbers to check since I had a lot of time left.</p>
<p>OMG awesome. So glad that at least a few of my guesses worked out. Hopefully I didn’t make mistakes in the early problems. -_- First math section had one or two that were difficult and confusing within the first 15 questions. I was like “***.”</p>
<p>T < R < P was definitely right.</p>
<p>1.2 was definitely right.</p>
<p>Anyone get 1440 as one of the grid in answers?</p>
<p>"The slope would get larger @MichaelGScarn. You could’ve just plugged the coordinates into your STAT function (assuming that you used a TI-83 or TI-84) and the slope went from .31 to .67. "</p>
<p>Yeah that’s what I was trying to say —> “I said the slope would increase”</p>
<p>I think the one about the point P said that point P is twice as far from 3 as from 0. I don’t remember the choices or what it was asking so could somebody help with that</p>
<p>yes @1440 gridin</p>
<p>I did, don’t remember what for hahah</p>
<p>@MichaelGScarn
The problem stated there exists a point P on a number line that’s twice as far from 3 as from 0. P could only be 2 points, which are -3 and 1. If you plugged in those 2 numbers only C worked.</p>
<p>I’m sorry I don’t remember the choices either. There were a lot of absolute values though haha</p>
<p>I got 1440 also.</p>
<p>Xerdge, A was |x-3|=2|x|. If you substitute -3, that’s |-3-3|=2|-3| -> 6=6.</p>
<p>What was the equation for C? I didn’t try that one so I might be wrong, but both 1 and -3 work for A.</p>
<p>The P coordinate one was definitely choice A.</p>
<p>wasn’t 8(pi -1) one of the answers?</p>
<p>@Xerdge</p>
<p>Oh okay yeah those are the two points I found so hopefully I got that answer</p>
<p>Does anybody remember the one problem with the two connected points that were 6 apart? I believe the question was asking how many points in between the endpoints of the line segment would be a distance of 3 from both points</p>
<p>“The P coordinate one was definitely choice A.”</p>
<p>You probably found only one point on the number line, 1, and not the second, -3.</p>
<p>^It was 16(pi -1).</p>
<p>For the 6-point line one I got “one point”.</p>
<p>No wasn’t it was like 2abs(x-3)=abs(x), which i think was c or d?</p>
<p>I said only 1 point for that @ Michael</p>
<p>Definitely one point for that one since the line was only 6 units and the midpoint could’ve been the only point that had 3 units on each side.</p>