<p>A wheel has a diameter of x inches and a second wheel has a diameter of y inches. The first wheel covers a distance of d feet in 100 revolutions. How many revolutions does the second wheel make in covering d feet?
A. 100xy
B. 100y - x
C. 100x - y
D. 100y / x
E. 100x / y</p>
<p>I got the answer correctly using this method, since the bigger the wheel, the less revolutions, its an inverse relationship. So insetad of solving for the circumference i just multiplied the diameter of the large wheel by its revolutions, and divided by the diameter of the small wheel to get the revolutions of the smaller wheel. Again, i did this because its an inverse relationship.
My question is this, on another problem, would this method WORK? would the distance D affect the answer? Im guessing that i can disregard D here since D is same for both. Im not sure tho.</p>
<p>This question is hard to answer, because it really depends on what the question is. There are other problems about wheels where the diameter might affect the answer.</p>
<p>Meh its simple to do with algebra… I would just do it like like this because I have no idea if yours will work, although I can see no reason for it not to.</p>
<p>I picked numbers for diameter; x= 10, y = 15.7</p>
<p>Solved for circumference, x circum = 31.4, y circum = 15.4</p>
<p>Solved for distance, 31.4 * 100 = 3140 = d</p>
<p>Set up algebra, 15.7 * x = 3140</p>
<p>x = 200 = # revolutons</p>
<p>Plugit in and only E works… Takes like a minute.</p>
<p>here’s what i did
let’s say x=2, y=4. So it says: The first wheel covers a distance of d feet in 100 revolutions. Just do 100x so 100 x 2 = 200. Now to do the same distance, how much would it take for the second wheel which is y. 200/4 = 50… now using the x and y values we created earlier, try to plug them in and find the answer that equals 50. And voila! E is 100(x)/y = 200/4 = 50!</p>
<p>algebraically,its something like this.
draw a picture of a big circle and a small circle.
big circle with diameter x, smaller circle next to it,with diameter Y.
the circumference of big circle, is X(pi), small cir = Y(pi)
imagine,if u unbend the circle,into a straight line, that’s how far the circumference is if its a line. uh…?? lol
this distance,is the circumference, which is also 1 revolution, yeah?
which is also x(pi), now thats 1 rev, theres 100rev,
100x(pi), that’s 100 circumferences.
theres the smaller circle, divide the smaller circumference, which will give u more than 100 rev,but same distance… ahh nevermind, lets use this other one.
(X pi) 100 = Distance
(Y pi) Z =Distance
Z is the revolution,which is unknown is this case. we dk how many rev for Y.
Distance is the same for both,but the revolution is different.
so now make the equations eqaul.
Xpi 100 = Ypi Z
Xpi 100 / (Ypi) = Z
X100/ Y = Z
Z is the # of revolutions.</p>
<p>d = distance to be traveled
d = 100 revolutions of wheel A
1 revolution of wheel A = circumference of wheel A
circumference of wheel A = 2(pi)(x)
d = 100 * 2(pi)(x)
d = 200(pi)(x)</p>
<p>Wheel B needs to travel distance d
d = circumference of wheel B * revolutions of wheel B
circumference of wheel B = 2(pi)(y)
200(pi)(x) = 2(pi)(y) * revolutions of wheel B
revolutions of wheel B = 100(x) / y</p>
<p>uhm , i think its quite easy to solve. Here: d= Circumference of the wheel * the number of revolution , so -> d= x.(pi) .100
let the number of revolutions of the second wheel is A :
We have: A . y. (pi) = d -> **A.y.pi = x.(pi). 100 **
=> **A= 100(x)/y<a href=“omit%20pi%20,%20right%20%5E%20%5E”>/B</a></p>
<p>A wheel has a diameter of x inches and a second wheel has a diameter of y inches. The first wheel covers a distance of d feet in 100 revolutions. How many revolutions does the second wheel make in covering d feet?
A. 100xy
B. 100y - x
C. 100x - y
D. 100y / x
E. 100x / y</p>
<p>100.pi.x = d
N.pi.y = d
N.pi.y = 100.pi.x
N = 100x/y …option (E)</p>