<p>Here are 4 more that have me confused:</p>
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<p>the answer to 19 is E</p>
<p>x^2 = 4(y^2)
(2y+1)^2 = 4(y^2)</p>
<p>graph the equations (2y+1)^2 and 4(y^2). Find the intersection to get the value of “y” (note: refer to the X value of the intersection for y). Once you got the value, plug it into 2y+1 and you should get 1/2.</p>
<p>Very smooth. Thanks.</p>
<p>i wouldnt consider those… “fun”</p>
<p>These are from the January 2007 test…
When I looked at #17, I didn’t even set up equations. I just noted that the 3 of the first rides minus 2 of the second rides would be the ride we are looking for. So to check, 3(5.5) - 2(4) = 8.50</p>
<ol>
<li><p>R = number of additional red taken. G = number of additional green taken.
3+R>4+G
G=13-R
3+R>4+13-R
2R>14
R>7</p></li>
<li><p>CostA(t)=CostB(t), given t>20
1+0.07(t-20)=0.06t
solve for t
t=40 mins</p></li>
<li><p>P=A
16k=10k^2
k=16/10=8/5</p></li>
</ol>
<p>19.x^2=4y^2, x=±2y
x=1+2y, y=(x-1)/2, 2y=x-1
x=±2y, x=±(x-1)
try x=x-1… impossible
try x = -(x-1), 2x=1, x=1/2</p>
<p>For 18. I put The perimeter and Area in terms of k</p>
<p>So there are 16 little k sides, so p=16k
and since the area of a small square is k^2 and there are 10 squares A=10k^2</p>
<p>Then since P=A: 10k^2=16K
Divide K to get
10K=16 and thus
K=16/10</p>
<p>I hope I didnt do anyhting illegal with the K’s</p>
<p>Is this a official test like a QAS? If so do you by chance have the entire thing scanned or are you willing to distribute some parts of it XD</p>
<p>sigh I misread the question… the one i did is for a different question…the taxi one</p>
<p>Thanks all.</p>
<p>I never would have thought to do the (t-20) thing… and never would have thought to do that on #15 either, lol. Figuring out how to set things up is the hardest part.</p>