<p>Ho:ETS will find me
Ha:ETS will not find me
<em>calculates</em>
P value is .000001
Since p value of .000001 is statistically significant at the .05 level, I am almost 99% confident that I can reject the null and accept the fact that ETS will never find me.</p>
<p>We’re not allowed to talk about the MC ever, and after 48 hours we can talk about the FR. However, I really don’t think they would be able to catch you.</p>
<p>Fckin bombed it. God I hate my life</p>
<p>the one about the cars, how do u find the probability??? i did binomial… it that right???</p>
<p>@rhdxogh3346 Bro why was it so hard for you?
I really didn’t study or pay attention, and I felt the exam was decent…</p>
<p>I mean I screwed up here and there, but I know I got a 3 or 4…</p>
<p>^um, that’s nice for you that you think you did well. not everyone feels that way. are you really expecting him/her to answer you…?</p>
<p>“Hey kids - if AP tracks your specific test discussions back to you, you are royally screwed and it could also jeopardize the test results of all your classmates.”</p>
<p>lol, this never happens, hun ;)</p>
<p>^What about that kid in the sticky thread?
^Yeah I mean its not really a personal question. I’m pretty sure they can answer…</p>
<p>^Come on now… Don’t discuss just yet.</p>
<p>This is a public forum, that collegeboard looks at.</p>
<p>Standard deviation conversion to Celsius???</p>
<p>I think I bombed the test. Hope everyone else didn’t answer every part of the free response so the test gets curved Its possible you plainly did bad becuase your teacher didn’t do enough reviewing</p>
<p>college board does not want you talking about the questions on the exam. You can still say if it was hard. Talking about specific questions may not be smart. For some people they may want their scores canceled. College board charges $15 to canceled grades from being sent. Maybe the easy way out is to get those scores canceled ha </p>
<p>anyway hopefully i pulled off 4 :(</p>
<p>COME ON!!! WHO THINKS COLLEGE BOARD OR ETS IS GOING TO TRACK THE PEOPLE WHO DISCUSS THE MCs! NOT even the E-mails like they said. if they enter to my email I sue them! hahahahah</p>
<p>When you manipulate a distribution in the manner ax + b, where x is the original value and a and b are factors by which the distribution is changed, the standard deviation is only multiplied by a, whereas the mean is multiplied by a and b is added to it.</p>
<p>^i don’t remember that question…oh god…D: : P</p>
<p>^ That was supposed to be for the one about the conversion to Celsius.</p>
<p>So you only multiply the standard deviation…</p>
<p>Eh, that car question got me. I used sigma / sqrt n for the st. dev and got something like 999 :(</p>
<p>I hope you were supposed to use the normal model for part b of that question :/</p>
<p>Other than that, I think I got everything right.</p>
<p>^ Apparently that question was binomial, so you do np for the mean and sqrt[n(p)(1-p)] for the standard deviation. I only did the np part. :</p>
<p>Then for the second part I just drew a normal curve because I ran out of time. :P</p>
<p>And on the third part, I also had very little time so I just wrote that we do a stratified random sample.</p>
<p>We aren’t allowed to be specific, but the MC was okay w/ a couple of tricks but the FRQ was terrible (expected b/c 2009 looked easy online)</p>
<p>but when it is “bad” the curve adjusts for it right?</p>
<p>I thought the FRQ’s were semi-decent. I got 50% of them, and I had no idea any of them had anything to do with binomial until now so I’m pretty much screwed.</p>
<p>What percentages do you need for a 2 or 3?</p>
<p>are you sure that was a binomial distribution?
the conditions of a binomial distribution are that there’s a certain number of trials, the probability of success/failure stays the same each time, each trial is independent, and the probability of success stays the same. </p>
<p>what i did was to calculate expected number was np, then for the standard deviation, i used sqrt ((p)(1-p)/n) </p>
<p>[The</a> Binomial Distribution](<a href=“http://www.stat.yale.edu/Courses/1997-98/101/binom.htm]The”>The Binomial Distribution)</p>
<p>“For large values of n, the distributions of the count X and the sample proportion p hat are approximately normal. This result follows from the Central Limit Theorem. The mean and variance for the approximately normal distribution of X are np and np(1-p), identical to the mean and variance of the binomial(n,p) distribution. Similarly, the mean and variance for the approximately normal distribution OF THE SAMPLE PROPORTION are p and (p(1-p)/n).”</p>
<p>since the sample size was 2000, CLT allows normal distribution, and this the mean and variance are normally distributed with mean = p and standard deviation = sq rt (p(1-p)/n)</p>