<p>hey all…
for those math geniuses out there i would really like it if one of u could really tell me what exactly is the Super Pythagoras Theorem… is it related to the actual pythagoras theorem and also are problems that involve the super pythagoras theorem present on the NEW SAT??</p>
<p>Had to know this one for 2c, its a^2 + b^2 + c^2 = d^2 for a rectangular prism with sides length a, b, and c and diagonal d (not the diagonal of a rectangle, its the diagonal from the top corner to the bottom corner of the other side - hard to visualize, try to google a pic). I think I used it once on 2c, but I don’t remember seeing it on 1…</p>
<p>thanks mate…</p>
<p>Whew, glad I didn’t have to use that on math 2c. I could find it out, but not as quickly as with that formula. I would’ve found the hyp of one side then used that along with the width to find the diagonal.</p>
<p>i actually came across it on a PR practice test… in the explations thats what they used…</p>
<p>Its just an extension of the pythagorean theorem into a third dimension. You can extend this theorem into however many dimensions you feel like (ex. a^2+b^2+c^2+d^2+e^2+f^2=g^2 would be six dimensions) making ‘uuber super duper pythagorean Theorums’, although its not really applicable to real life past 3; everything beyond that is theoretical math.</p>
<p>intersting thoughts there… dmk092 if possible cud u gimme a few sites where i cud practice problems associated wit this theorem…</p>
<p>Hmmm…
I dont know where you would find problems, though I seem to remember using it on a few integrals at the end of last year. I guess a really simple problem of this type might be:
What is the diagonal (or the equivalent) of a five dimensional rectangular solid with the following characteristics: 3, 2, 3, 5, 1
Answer in next post</p>
<p>48^.5, or 4*(3^.5)</p>
<p>umm… how did u get that???</p>
<p>a^2+b^2+c^2+d^2+e^2=f^2
3^2+2^2+3^2+5^2+1^2=(48^.5)^2</p>