<p><a href=“http://dbhs.wvusd.k12.ca.us/ourpages/auto/2010/4/19/53452872/C2%20TakeHomeTest_MultCh_part1.pdf[/url]”>http://dbhs.wvusd.k12.ca.us/ourpages/auto/2010/4/19/53452872/C2%20TakeHomeTest_MultCh_part1.pdf</a></p>
<p>Please answer number 24</p>
<p>can anybody solve this noncalculator problem (mc) </p>
<p>Find the area of the inner loop of the polar curve r=1+2cos(theta)
a)2pi
b)2pi - 3(sqrt(3))
c)3pi
d)pi + (3sqrt2)/2
e)pi - (3sqrt2)/2 </p>
<p>question’s ■■■■■■■■ because you’re supposed to find limits of the inner loop of the graph, as in the limit is not 0->2pi</p>
<p>edit: btw, the answer is (e) i just don’t know why</p>
<p>probably a stupid question, but how often do polar coordinates show up on the BC exam?</p>
<p>24) You know the derivative equals 0 when P=200 (i.e. never does, but it gets really close). Plug 200 into the dP/dt until dP/dt=0.</p>
<p><a href=“http://dbhs.wvusd.k12.ca.us/ourpages/auto/2010/4/19/53452872/C2%20TakeHomeTest_MultCh_part1.pdf[/url]”>http://dbhs.wvusd.k12.ca.us/ourpages/auto/2010/4/19/53452872/C2%20TakeHomeTest_MultCh_part1.pdf</a></p>
<p>can someone do 22? dont get it</p>
<p>integration by parts
so uv-∫vdu
dv=f’(x)
u=g(x)
so f(x)g(x)-∫f(x)g’(x)=5
∫f(x)g’(x)=f(x)g(x)|0->1 - (5)
use the table to find the integral of f(x)g(x) from 0 to 1 which is 20
so ∫f(x)g’(x)=20-5 = 15 answer is (e)</p>
<p>It’s integration by parts. Kinda tough to type all that into here :o</p>
<p>How would I go about doing these problems?</p>
<p>1) What is the sum of the series 1+ ln2 + (ln2)^2/2+… (ln2)^n/n!+…?</p>
<p>a) ln 2
b) ln (1+ln2)
c) 2
d) e^2
e) the series diverges.</p>
<p>Let R be the region between the graph of y= e^-2x and the x-axis for x greaterthan/equal to 3. The area of R is.</p>
<p>a) 1/(2e^6)
b) 1/e^6
c)2/(e^6)
d)pi/(2e^6)
e) infinite</p>
<p>thanks</p>
<p>the first one is:
c) 2</p>
<p>because the series for e^x is (x^n/n!)
What you are given is basically that with ln(2) replaced for x
so x=ln(2)
e^(ln(2))=2 <– this is your answer</p>
<p>For the second:</p>
<p>it’s going to be the integral of e^-2x from x=3 to infinity. plug in b for infinity and take the integral of e^-2x as lim of b–> infinity.</p>
<p>The integral of this is -(e^(-2x))/(2) from 3 to b as the lim of b –> infinity.</p>
<p>so when you plug in b for x and plug in the limit of b as infinity, you get 0 and then plug in 3 for x and you get -(1/2e^(6)) . well since taking it from 3 to b means plugging in b then minusing the 3. you get 0 - (-(1/2e^(6))) = 1/(2e^6) </p>
<p>this is a)</p>
<p>hope it is clear.</p>
<p>
</p>
<p>R goes from 3 to infinity since (e^-2x = 1/(e^2x) and this doesn’t actually go to 0)</p>
<p>Therefore, all we have to do is integrate y= e^-2x from 3 to infinity.</p>
<p>Antiderivative of y= e^-2x is y = (e^-2x)/-2 = F(x).</p>
<p>Now we evaluate for (lim as b -> infinity) F(b) - F(3).</p>
<p>This gives us (lim as b -> infinity) of (1/-2(e^2b)) - (1/-2(e^6)).</p>
<p>(1/-2(e^2b)) goes to 0 as b goes to infinity, so we’re left with:</p>
<p>(1/-2(e^6)) = a) 1/(2e^6), I think.</p>
<p>Are we sure that pressure/work problems aren’t kosher for BC? I’m pretty comfortable with volumes and related rates, but the physics aspects of those problems always kill me.</p>
<p>work= f x d. but i’m sure it’s not on the BC calc exam, unless it is some wicked free response question. But then they would give you some crazy equation for work and not make you do the physics part.</p>
<p>anyone have a good power series question to share? I’m willing to place bets that that is the last free response question.</p>
<p>I think if work/pressure other physics related topics were on the exam, they would tell you that Work equals force times displacement or any other information necessary to complete the problem</p>
<p>Does anyone know how often questions about the Lagrange Error Bound are on the test? If they’re common, could someone give me a brief explanation of how to use it please?</p>
<p>I’ve been working through all released FRQs, and the 2007 set seemed particularly brutal. Is that just me? Everything else seems pretty straight forward, but I had a hard time with that one.</p>
<p>LaGrange error bound: Usually one multiple choice question/one part of an FRQ from what I’ve seen</p>
<p>I plan on just skipping it haha</p>
<p>
</p>
<p>lmao glad I wasn’t the only, the piece-wise function rate question really owned me lol, I had to really think about it.</p>
<p>The polar stuff I didn’t even know what it mean when it asked to express it in terms of etc…</p>
<p>Guys, for maxima questions, are yuo allowed to use set notations like [(…)] and can you use test points to justify your answers instead of saying like f’'(x) > 0, so it concaves up etc…</p>
<p>you can use both set notation and interval notation, for example 0<x<1 is the same as (0,1). For concavity, well, I think the graders want to see the use of f’'< 0 and such to see if you understand why f is concave up or down.</p>