<p>Yeah, my teacher just told me that a number line/sign chart was not substantial for justifying answers for extrema, but you should be fine if you mention if either the first or second derivative test was used.</p>
<p><a href=“College Board - SAT, AP, College Search and Admission Tools”>College Board - SAT, AP, College Search and Admission Tools;
<p>Question 1, part c, how did they get the limits of T-2 and S-2?</p>
<p>^They used a calculator, just graph the functions together and check the intersections.</p>
<p>who has the 2003 FRQ scoring guideline? I’m stuck on 2b already : /</p>
<p>^<a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board;
<p>Good luck</p>
<p>Question… when doing Polar Area, how do you know what the to integrate to and from? thanks.</p>
<p>@hellohellicopter, no one knows. Nah I am kidding, usually I would just estimate from the graph or put it back into</p>
<p>y = rsinx
x = rcosx</p>
<p>Just bet on one of those equations hit the x axis, if neither of them does, then you are screwed lol</p>
<p>If a function is differentiable at a particular point, does its derivative need to be continuous at that point? Examples of functions where this is not true</p>
<p>its when one of the equals zero… right? EH POLAR IS LAME.</p>
<p>Can someone explain to me how to use 6a to get the answer to 6b on the 2009 FRQ?</p>
<p><a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board;
<p>My class didn’t cover Taylor series that thoroughly.</p>
<p>hellohellicopter- yes, its the first two times when r=0. my teacher taught us a little trick - 95% of the in a noncalculator section when its asking for area for polars, the limits of integration will be from 0 to 2Pi, and in the answers, it will be a form of 0 to 2Pi.</p>
<p>how do you get from 6a) to 6b)? in the 2009 test. </p>
<p>the link is posted a couple posts above mine.</p>
<p>Plug some of the terms from the answer to 6a into the function in part b, while leaving the rest alone. The 1 of the 1st term cancels with the 1 at the end of the numerator. Then, divide everything by the denominator and generate your new series.</p>
<p>@motivated_101</p>
<p>You put your answer from question 1 into the function f (where it says e^(x-1)^2). The 1’s subtract out, and you can divide every term in the taylor series (from 6a) by (x-1)^2</p>
<p>I have a rough memory of doing this problem for a calc quiz last week, but heres what I remember:</p>
<p>From 6a to 6b, they are asking you to find the value of (e^((x-1)^2)-1)/((x-1)^2). Since you have the approximation for e^(x-1)^2, you will subtract 1 from the series, which eliminates the first term in 6a. Then you divide each term by the (x-1)^2, which lowers each exponent by 2.</p>
<p>Thanks so much!</p>
<p>Can someone help me with finding volumes of known cross sections? If i understand, I find the forumula of the base (triangle/circle/etc) and integrate it from the intersection points. Is that how it works</p>
<p>
</p>
<p>What if you have this?</p>
<p>x = theta</p>
<p>r = x + sin2x</p>
<p>0 = x + sin2x</p>
<p>-x = sin2x</p>
<p>x = 0, only, but it has -pi as an answer?</p>
<p>
</p>
<p>Can you clarify this a little bit? I can’t really tell what you’re asking :x</p>
<p>If you have your limits of integration from 0 to 2pi and the answer has things like 0 to pi, try to change your integral around. So if you have 1/2 Integral 0 to 2pi of cosine, then you can change that to the integral from 0 to pi of cosine. Its always a simple change to change limits of integration.</p>