there's no way to differentiate x^x right?

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1

<p>title says all</p>

2

<p>you can do it logarithmically</p>

<p>if y= x^x
lny = lnx^x
lny = xlnx
then differentiate
1/y * dy/dx = lnx + 1
dy/dx = y(lnx +1)
dy/dx = x^x * (lnx+1)</p>

3

<p>thanks i didnt even realize that.</p>

4

<p>I don’t remember that on the SAT?</p>

5

<p>Calculus owns you.</p>