<p>It says that YS split their cross-admits. It then tells you what number of students picks Y over S and the % of non-enrolling students who picked Y. You can then find the total number of non-enrolling students. You can then find the number of non-enrolling students who picked P over S. Unless the number of PS cross-admits is significantly higher than that of YS cross-admits, P wins the battle (also, why would Mr. Shaw mention Y but not HP if they beat them in cross-admits?). </p>
<p>And I’m honestly not bashing S, I almost chose it. And you’re right, we don’t technically know. But given what we do know, I don’t think it’s a stretch.</p>