<p>This is from Barron’s Model Test 7, #48. Page 272.</p>
<p>Each of a group of 50 students studies either French or Spanish but noth both, and either math or physics but not both. If 16 students study Fr and math, 26 study Span, and 12 study physics, how many study both Span and physics?</p>
<p>(A) 5
(B) 6
(C) 8
(D) 4
(E) 10</p>
<p>50-12 = 38 study math
16 study fr/math, so 38-16=22 must study sp/math
the 26 who study sp can be either sp/math or sp/phys
26-22 sp/math = 4 sp/phys</p>
<p>or:</p>
<p>50-26=24 study Fr
16 of Fr’s study math so 24-16=8 study Fr & Ph</p>
<p>12 total study Ph and 8 of them study Fr so the remaining 4 must study Sp.</p>
<p>4 students study Sp and Ph.</p>
<p>I admit I took a couple minutes on this one, so in SAT terms it is freakish.</p>
<p>Oh, ok. That really helps. Much better than Barrons stupid explanation :)</p>
<p>lol barron makes the real sat math look like a joke</p>
<p>Well that’s what I’m hoping! I’m going for that 800 :)</p>
<p>Freakish? Perhaps not to that degree, but it is somewhat challenging in SAT terms. This would probably be only #1 or 2 on an AMC test though.</p>
<p>I don’t think it is a particularly hard problem, but the short time provided on the SAT is what makes in difficult, IMHO.</p>
<p>Yeah, that’s what I thought… I don’t anticipate finding anything that bad on the real thing though, since that was close to the last problem in a Barron’s book.</p>
<p>Thanks anyway :)</p>
<p>nvm…i should read the question completely first</p>