<p>Keasby, I confirm 2x^2*sqrt(1 - x^4)
It checks out on the calculator.</p>
<p>for the average speed one 60mph and 40mph, it was exactly 50 because it traveled the same distance?</p>
<p>Yea I got 2x^2*sqrt(1 - x^4) too.</p>
<p>
</p>
<p>…What? 1/g(x) is a reciprocal, not an inverse. HUGE difference. At x = 3, the graph hits a vertical asymptote because you have a non-removable discontinuity (the discontinuity, 1/0, is determinate, meaning that an asymptote exists).</p>
<p>superexcited, that problem didn’t ask for the inverse, but the reciprocal.</p>
<p>the question that had a triangle and then two equal angles in them, what was that?
i said </p>
<p>A which I think it was Sin 2 theta.</p>
<p>Stonesn - I got less than 50 mph, because you traveled at 40 mph at a longer time, and average speed is (total distance/total time).</p>
<p>Yeah, keaseby, I drew a triangle with x^2 as the opposite and 1 as the hypotenuse. Then I used the double angle formula for sin. 2sin(t)cos(t)</p>
<p>If it is 1/0 then how is f(x)=0?? wouldn’t f(x)=undefined since 1/0 is undefined.</p>
<p>it was asking for g(x), not f(x)</p>
<p>was the last one D
because i made a random guess and idr what D said</p>
<p>It was 2sin(theta), not sin(2theta)</p>
<p>The problem didn’t ask for the point where f(x) = 0, I’m almost positive. If I’m wrong, then whoops. But the problem certainly did not ask for an inverse.</p>
<p>for the line AB, what was the answer, it was with 2 theta. plus was the parametric equation: 1/3 or 1/2. tHANKS!</p>
<p>thisisauser: yea i think you’re right.
that was option A right?</p>
<p>So wait was there two answer choices like “less than 50” and “equals 50” or was it the same choice.</p>
<p>FEW!! I put 0 even though I misread the question that it was asking for f(x)</p>
<p>Malfunction - There were two choices.</p>
<p>so, the g(x) one was 2…?
AHHH.</p>
<p>I got 12, how does 10 work ?</p>