<p>0 was definitely not the answer it was 2 or 3</p>
<p>Wait, so what’s the answer to the g(x) question? The more I think about it, the more I’m forgetting.</p>
<p>what? For the period question? 2sintheta just makes the graph’s range longer.
sin(2theta) changes the period.</p>
<p>It’s 3 because there was a vertical asymptote there.</p>
<p>That’s right RustGust.</p>
<p>The g(x) question was 3.</p>
<p>What’s a parametric equation? We never learned about that in school =(</p>
<p>RustGust</p>
<p>there were two equations. one of them- the graph one- was sin2theta because it was about the period</p>
<p>and the other question- the triangle one was 2 sin theta. which was choice A.</p>
<p>@rustgust, I’m talking about the one with the triangle with line segment AB</p>
<p>What did you guys get for this problem?</p>
<p>f(x) = f(x+1)/2 and f(2) = 4
f(3)-f(1) = ??</p>
<p>I can’t believe so many people got the answers by plugging into a calculator - especially the absolute value and ln x = e^(-x) ones. Some of the problems described were definitely solvable without a calculator.</p>
<p>Sometimes I wish that the SAT IIs were entirely non-calculator, to conform with other types of math competitions (the ISMTF and UKMT to name a few). After all, plugging into a calculator or programming a solution beforehand involves little mathematical thinking and analysis on testing day. Not to mention that the latter should count as an unfair advantage (again, why don’t we clear calc data on the day of the test for TI calculators? Beats me)</p>
<p>what did people get for 49?
I dont’ even remember the question, but I answered it.</p>
<p>f(3) - f(1) = 6</p>
<p>evillion: the answer was 6</p>
<p>
</p>
<p>This test is not a math competition, nor is it designed to assess students’ mathematical reasoning – it’s an achievement test.</p>
<p>how is that question =6</p>
<p>i put that the variable is greater than or equal to 3</p>
<p>f(3) - f(1) = 6 … Agreed</p>
<p>Also, parametric equation, i got -1/3, pretty confident that’s right.</p>
<p>basically for parametric equations you just solve for t in both equations and then make them equal to each other- we haven’t done that either, but it seems logical.</p>
<p>Yeah I also got x>=3.</p>
<p>(|b|-|ab|)/|a-1|</p>
<p>=(|b|-|a|*|b|)/|a-1|
=(|b|(1-|a|))/|a-1|
//a was positive right?
=(|b|(1-a))/(a-1)
=(-1|b|(a-1))/(a-1)
=-b</p>
<p>Can someone check my math? or show how they got b instead of -b?</p>
<p>that wasn’t too bad. So I forgot to answer #4.,I didnt do 46 and 47. As for the rest,i’m guessing i got the disk one wrong, the average rate one,and then this other one. So I’m guessing a 790?</p>