<p>1)and the answer to 12/100 and 13/100
between .12-.13 is .123
also…
2) probability of picking a number that is a multiple of three
2/7
3) probability that a house has exactly one telephone, 1/4
4) dimensions of the rug 8 by 14 was it?
Did anyone remember that chapter question with the book. was the answer 80 pages?</p>
<p>Yeah, the answer was 80 pages. And the answer to your 1.) was 12 because you wanted to find x where .123 is between x/100 and x+1/100.</p>
<p>There was also that question with a line, A__<em>__B</em><em>C</em>____D and you were given the lengths of each segment. Which length can you not measure using this “ruler”?</p>
<p>I remember it being D, maybe? But I don’t remember any of the lengths or the answer choices. Actually, I think they all added up to 11 (and that was answer choice E). Anybody else remember something about this one? It wasn’t hard, but at least it’s another question to be added to the list.</p>
<p>no the books question’s answer was 500 pages</p>
<p>it asked by how many pages the book would decrease if they increased the line number to form like 50 to 54</p>
<p>answer was 9</p>
<p>i dont recognize your question at all! collegefreak</p>
<p>was it section 1 or 4(or 5) that was experimental for the people with four math sections</p>
<p>we got five questions down from the mc
the pencil one: all three
the one before pencils: 50
23. what was the question
22. E
21. </p>
<p>1) 2.5 hours
2) 110 degrees
3) calenders 3(2r+x)
4) reflection which i got A
5) 80 pages
6) y=1 or negative one, cant remember
7) it cant have a remainder of 5
8) probability of chooses a multiple of three, 2/7
9) rug problem 8 by 14
10) telephones, 1/4</p>
<p>Ok can someone please explain how you got the answer 5/64 for the final grid in I can’t seem to get that answer for the life of me. Maby I just missed something in the problem but I would like to see how you got it</p>
<p>Well it had a lot of “/8” answers so I just used 64.</p>
<p>(3/8) * 64 = 24</p>
<p>64 - 24 = 40</p>
<p>(7/8) * 40 = 35</p>
<p>40 - 35 = 5</p>
<p>you started with 64 and have 5 left. Therefore you have 5/64 of the original</p>
<p>tongos, i think it was y=1</p>
<p>AGH!!! I put 5 as the answer for that 5/64 problem. Jesus, kicking myself in the head as well as that 125 one. I put 225 for that one as I counted 25 for the first set of 3 digit odd numbers and multiply by 9, but I needed to multipy by 5 because it said ODD. JESUS!</p>
<p>I just totally blanked on that problem (5/64). I thought, “I know this is an incredibly easy problem… but… arr!” so I put in some random fraction. And of course in a later verbal section I was checking all of my math answers and I figured it out. Grrr. So so far I have 1 “omit” since grid-ins don’t take any extra points away…</p>
<p>How is (-3, 2) closest to the x-axis? I made a graph and plotted all the answer choices and the one that made sense was the point (1,1) or was it (-1, 1) but that answer was closest to the x-axis. How is (-3, 2) closer to the x-axis than (+/- 1, 1)?</p>
<p>And for that train problem, I still think it’s 1000 feet. Reason being is that the train is 200 feet and the time was counted from where the front of the train entered the tunnel to the point where the back of the train left the tunnel. Question was how long is the tunnel. Since it said it took 70 seconds and the rate was 20 m/s, I divided 200 feet by 20 to get 10 seconds. That 10 seconds cover how much time it took for the entire train to be inside the tunnel from the beginning. Then you apply that to when the timer stops when the back of the train leaves which takes another 10 seconds. So that’s 20 seconds together shaved off. Then we only have 50 seconds left which I multiplied by 20 and got 1000 feet since the question asked what the length of the tunnel was. Correct me if I made a mistake but I feel this is the answer.</p>
<p>-Oh and on that cone & cylinder problem. It said that there is a cone and a cylinder with both the same height and radius. And the question asked what the length of segment PR for the cone was and QS (dunno about the letters but it’s a variable) for the cylinder. So I just plugged in values. I put the value of 1 for the radius and 2 for the height. And point P was plotted on the top of the cone and point R was NOT plotted on the center but on the edge. So, considering that, I put the length of segment PR was 2 because that would be equivalent to the height since the radius isn’t counted. </p>
<p>Now, for the cylinder. The point Q WAS plotted IN THE CENTER of the top circle and point S was on the edge at the bottom. So considering that, I took 1(point Q) + the height 2(point S) and got 3. Thus, I got the answer that B (cylinder) was greater. I did put C at first that they were the same length but I rechecked and thought that couldn’t be. The fact is that the radius was counted and the height. Correct me if I’m wrong.</p>
<p>left 3 and up 2… you are closer to the x-axis.</p>
<p>i dont understand either, but i am sure the answer is probalby /3,2 , i thought it was 1,1</p>
<p>the reason i thought it was 1,1 is because i took the distance of how far it would be from the closest thing on the x axias and that was shorter than any other??</p>
<p>Can somene explain that problem? I guess i am over looking it…</p>
<p>I still don’t understand. I’m not trying to stir up an arguement, but I don’t see how that is. When the question says what point is closer to the x-axis, isn’t it asking who is closest to that x-line, you know when you draw a graph you draw an x-axis and y-axis. Ok, so how can the value of 2 be closer than the value of 1. 1 is closer to the x-axis. I don’t see how 2 is closer? The point (1, 0) would be on the x-axis. But let’s say there is two points (1, 1) and (1, 2). Which is closer to the x-axis? It has to be the (1, 1). I don’t see it, so please explain this if willing.</p>
<p>e123, same here. I just don’t agree with that answer (-3, 2)</p>
<p>nope its definatly 1200, i remember getting that question write last time i took it.</p>
<p>i think i missed 9 to 11 on the math, any idea what my score would be? thanks for the input</p>
<p>tongos: would you be so kind to explain why my reasoning does not work? Thanks.</p>
<p>
</p>
<p>OK so circumference of a circle is 2pi(r). Perimeter of square is a+b+c+d (same values). So let’s say the circumference of the circle is 8pi. That means the radius has to be 4. Now the perimeter of the square has to be 8pi as well so we’ll use the value of 2pi for each side. Now that’s settled.</p>
<p>Now, it asks for area of circle vs area of square. So lets see. The radius is 4 so we multiply r^2 which is 16 and multiply that by pi. The area of that is 16pi. Now let’s take the area of the square which is length X width. So multiply 2pi X 2pi which is 4pi^2. Answer A is bigger.</p>
<p>you can also look at t in terms of efficiency. a circle more ‘efficiently’ uses space than a square. (in terms of perimeter vs. area)</p>